一、需求

需求很簡單，就是需要查詢一個報表，只有1個表，數(shù)據(jù)量大約60萬左右，但是中間有些邏輯。

先說明一下服務(wù)器配置情況：1核CPU、2GB內(nèi)存、機械硬盤、Sqlserver 2008 R2、Windows Server2008 R2 SP1和阿里云的服務(wù)器，簡單說就是阿里云最差的服務(wù)器。

1、原始表結(jié)構(gòu)

非常簡單的一張表，這次不討論數(shù)據(jù)冗余和表字段的設(shè)計，如是否可以把Project和Baojian提出成一個表等等，這個是原始表結(jié)構(gòu)，這個目前是沒有辦法改變的。

2、查詢的sql語句為

select *from(
select *,ROW_NUMBER() OVER (ORDER BY sc desc) as rank
from(
select *,
case when ( 40-(a.p*(case when a.p > 0 then 1 else -0.5 end)))<=30
then 30
else ( 40-(a.p*(case when a.p > 0 then 1 else -0.5 end)))
end as sc
from (
select * from (
select a.ProjectNumber, a.ProjectName, a.BaojianNumber, a.BaojianName, a.ToubiaoPerson,
sum(UnitPrice) as sumPrice,
b.price as avgPrice,
((sum(UnitPrice)-b.price)/nullif(b.price,0)*100) as p,
sum(case when UnitPrice>b.price then b.price else UnitPrice end )as pprice,
sum(case when UnitPrice>MaxPrice then 1 else 0 end ) as countChao
from ToubiaoDetailTest1 a
join (
select ProjectNumber, ProjectName, BaojianNumber, BaojianName, avg(price) as price
from(
select * from(
select ProjectNumber, ProjectName, BaojianNumber, BaojianName, ToubiaoPerson,
SUM(UnitPrice) as price,
SUM(case when UnitPrice>MaxPrice then 1 else 0 end ) as countChao
from ToubiaoDetailTest1
group BY ProjectNumber, ProjectName, BaojianNumber, BaojianName, ToubiaoPerson
) tt
where tt.countChao = 0
) t
group by ProjectNumber, ProjectName, BaojianNumber, BaojianName
) b
on a.ProjectNumber=b.ProjectNumber and a.ProjectName=b.ProjectName and a.BaojianNumber=b.BaojianNumber and a.BaojianName=b.BaojianName
group by a.BaojianNumber, a.BaojianName, a.ProjectNumber, a.ProjectName, a.ToubiaoPerson, b.price
) tt
where tt.countChao=0
) a
) b
) t
order by rank